RTC-4543SA

[Ttelmah]

37 decimal, becomes 0x37, when converted to BCD.
So, 0x25 -> 0x37.
Basically, the decimal 'tens', become the top nibble in the BCD number.
If you print a BCD number as Hex, you should see the original decimal number.
So, '16' in decimal, becomes 0x16. 22 in decimal.

Best Wishes

[Tagge]

Thanks Ttelmah, you are right.
One more question, in the CCS manual the function shift_right() is described as:
Function:
Shifts a bit into an array or structure. The address may be an array identifier or an address to a structure (such as &data). Bit 0 of the lowest byte in RAM is treated as the LSB.

It shouldn't mean that one can't shift bits into an single byte? It's no difference to a byte as a member in a struct?
For ex, data is only one byte. And there is no need for the data to be global?
shift_right(&data,1,input(RTC_IO));
It says: from PIN RTC_IO shift 1 bit to data.
By doing it 8 times, it's a whole byte.

Reason I'm asking is that I'm confused about the shifting in to the RTC, first byte of data is only 7-bits and a '0', second is 7-bits and a NC(No care), third 6-bits + 2 NC, fourth 3-bit + 1 NC(4-bits),, fifth 6-bits + 2 NC, sixth 5-bit + 2NC + a '0' as MSB, and the seventh is 8-bits of data.
I found out that the time as well isn't ok after all, after 59 min it can move over to 60, 61 and so on, same for the hours..
Only thing working is seconds...
Sorry to be a pain in the a.. about this..