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Reading Analog Input

 
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amjad_alahdal



Joined: 19 Feb 2013
Posts: 50

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Reading Analog Input
PostPosted: Sun Feb 24, 2013 7:26 am     Reply with quote

I'm using PIC 18F2455 ,,
I wonder if the following is the right code to read analog input:
Code:


#include<18F2455.h>
#device adc = 10

#fuses HS,NOPROTECT,NOWDT,NOLVP
#use delay(clock = 8000000)

void main()
{
   unsigned int16  value;
   setup_adc(ADC_CLOCK_DIV_32);
   setup_adc_ports(AN0_TO_AN2|vss_vdd );
   set_adc_channel(0);\\ The pic will read from A0 ?
   while(true)
   {
   delay_ms(100);
   value=read_adc();
     printf("%Lu",value);
      delay_ms(500);

   }
}
temtronic



Joined: 01 Jul 2010
Posts: 9243
Location: Greensville,Ontario

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PostPosted: Sun Feb 24, 2013 7:47 am     Reply with quote

There is no better teacher than 'hands on' experience.
That being said, I suggest you...
1) cut code for a 'blinking LED' program. This would confirm that your harware is wired correctly,fuses are right,etc.
2)Next, cut code for the 'Hello PC' test.This will confirm your commincations to a PC via the UART.
3)Then rewire to allow access to the ADC section of the PIC.

Doing small steps, you can get a 'feel' for how both hardware and software work.

hth
Jay
amjad_alahdal



Joined: 19 Feb 2013
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PostPosted: Sun Feb 24, 2013 7:53 am     Reply with quote

The problem is when I try to read analog signal from SHARP IR , The signal is supposed to be legal. What happens is all the time , the output is wrong. I thought that the part of reading the analog signal is wrong.
Speaking of the Steps that I should follow.
I do exactly what you have mentioned above. Because , I always don't expect a long program will be working well from the first time.

Thank you
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Sun Feb 24, 2013 8:52 am     Reply with quote

What you post should work.

Remember though that you are using the supply at the PIC as your 'reference'. Unless this is very nice and smooth, this will lead to less than perfect results.

Also, what is the output impedance of the sensor?. The PIC requires a relatively low impedance to drive the ADC. Do a test with something like a pot, and prove that the ADC is working as expected.

and, 'yes' as written, the ADC will read from A0.

Best Wishes
SherpaDoug



Joined: 07 Sep 2003
Posts: 1640
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PostPosted: Sun Feb 24, 2013 11:54 am     Reply with quote

You say the result is "wrong". What sort of "wrong" is it? What are you expecting? Is the output close? Is it always high or always low? Is it too noisy? Can you give us some sample output?
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amjad_alahdal



Joined: 19 Feb 2013
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PostPosted: Sun Feb 24, 2013 12:05 pm     Reply with quote

The entire code is supposed to read analog signal from Sharp IR. Then I multiply the result coming by a factor. This factor is written down in the Sharp IR. The result of the multiplication is supposed to give me the correct distance between the IR and the object.
If I go to what my program is supposed to do , it'll be as the following.
1- Set A0 to read Analog
2- set channel 0
3- read result from A0 put it in a variable x
4- multiply x by factor
5- print out the result
----------------------------------
amjad_alahdal



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PostPosted: Sun Feb 24, 2013 12:11 pm     Reply with quote

Furthermore, I connected the Sharp IR output to A0 Directly
temtronic



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PostPosted: Sun Feb 24, 2013 12:55 pm     Reply with quote

Get rid of the sensor and put a pot in FIRST !

Run a test program to read and display the voltage on the wiper of the pot which is connected to, say analog input #1.

Measure the wiper's voltage and compare the displayed value. If Vref is Vdd (+5), then an input of 2.55 volts should be 512 bits (1/2 of 1024).

Once you've confirmed this is so THEN rewire the Sharp sensor as the input. Be sure to read the datasheet! You might need an op amp buffer.

hth
jay
Mike Walne



Joined: 19 Feb 2004
Posts: 1785
Location: Boston Spa UK

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PostPosted: Sun Feb 24, 2013 2:03 pm     Reply with quote

This smells like a duplicate of thread you've already got running.

Please clarify.

Mike
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