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timer 1 interrupt

 
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MAKInnovation



Joined: 16 Nov 2010
Posts: 61

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timer 1 interrupt
PostPosted: Sat Jan 18, 2014 3:59 am     Reply with quote

Dear Friends;
Code:

#define USE_WITH_PC 1
#include <18F452.h>
#fuses HS, NOWDT, NOLVP, PROTECT
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, errors)

//RTC variables
#define XTAL_FREQUENCY  20000000
#define TIMER1_FREQUENCY (XTAL_FREQUENCY / 4)      // 1 clock tick = 1 instr. cycle = crystal frequency / 4
int32 Ticker;
int8 Seconds=0;

 ////////////////////////////////////////////////////////////////////////////////
 //    Initialize RTC
 ////////////////////////////////////////////////////////////////////////////////
 
 void Initialize_RTC(void)
 {
   Ticker = TIMER1_FREQUENCY;                  // initialize clock counter to number of clocks per second
   
   setup_timer_1( T1_INTERNAL | T1_DIV_BY_1 ); // initialize 16-bit Timer1 to interrupt
                                               // exactly every 65536 clock cycles
                                               // (about 76 times per second)
   enable_interrupts( INT_TIMER1 );            // Start RTC
 }

#org DEFAULT
 
 // Timer 1
 #org 0x1000, 0x1FFF DEFAULT
 #int_TIMER1                               
 void TIMER1_isr()                         
 {
   Ticker -= 65536;// Decrement ticker by clocks per interrupt
   if ( Ticker < 65536 )                   // If second has expired
   {  Ticker += TIMER1_FREQUENCY;          //   Increment ticker by clocks per second
      seconds++;                           //   Increment number of seconds
   }
//---------   Some code -----
   if (Seconds == 30) {Seconds=0;}
 }

////////////////////////////////////////////////////////////////////////////////
 // MAIN Program
 ////////////////////////////////////////////////////////////////////////////////
 void main()
 {
 int8 prev_second;
SET_TRIS_C( 0x8F );

   
   Initialize_RTC();
   enable_interrupts( GLOBAL );

   while(1)
   {
     if (seconds != prev_second)
     {
      prev_second = seconds;
   // -------- some code ---------- 
     delay_ms(10);
     }
   }
 }

I am using a very common timer code for my project. this code generates interrupt about 76 times per second.
which is slow for some of my calculation.
I want to generat interrupt about 800 times per second. How can i do this. Kindly resolve my issue.
Regards;
Ashraf
Ttelmah



Joined: 11 Mar 2010
Posts: 19535

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PostPosted: Sat Jan 18, 2014 4:19 am     Reply with quote

Use timer2.

Unlike the other timers, this one can be programmed for a specific count, rather than 65536.

setup_timer_2(T2_DIV_BY_4, 155, 10);

Will give an interrupt at 801Hz.

(((20000000/4)/4)/156)/10 = 801.28

However a much nicer number to work with is 1000Hz, since this divides evenly into the master clock/4.

setup_timer_2(T2_DIV_BY_4,249,5);

Remember though that it takes typically 60 instructions to get into and out of the interrupt handler, so the chip will be spending about 1.5% of it's time just handling the interrupt.

Best Wishes
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