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christoph
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| output of an 8bit integer as ascii on rs232 |
 Posted: Thu Jan 19, 2006 2:54 am |
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hello!
i�d like to print out the status of the whole port_b using input_b(). this returns a 8bit integer. now i will send this value over rs232 in ascii format.
i searched in the posts for integer to char conversion but i can�t find the correct answer.
can anybody help me?
thanks a lot in advance |
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kypec
Joined: 20 Sep 2003
Posts: 54
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| Posted: Thu Jan 19, 2006 4:01 am |
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| Look at the built-in printf() function and its arguments. |
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christoph
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| Posted: Thu Jan 19, 2006 5:06 am |
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okay...thank you! as you can see i�m beginner in programming.
i have read the help about printf but i �still can�t get it working...
would you post me an example? |
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kypec
Joined: 20 Sep 2003
Posts: 54
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| Posted: Thu Jan 19, 2006 5:16 am |
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| Code: | printf("%u",input_b()); //outputs 8-bit value of PORTB as ASCII string consisting of 1 to 3 characters
printf("%03u",input_b()); //outputs 8-bit value of PORTB as ASCII string with fixed length = 3 characters with leading zeros |
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christoph
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| Posted: Thu Jan 19, 2006 6:18 am |
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thank you!!
i tried you code but with this i don�t get for example "10011100" representing the the port status return - i get the decimal value in ascii-text.
i want to havefor RS232 in ascii: for exampe "Input-Status PortB is 10011100"
so i need a conversion from the 8bit integer to a char-array with 8 records.
you know what i mean? i�m right? |
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christoph
Guest
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| Posted: Thu Jan 19, 2006 6:19 am |
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| decimal value between 0 and 255 to be correct. |
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kypec
Joined: 20 Sep 2003
Posts: 54
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| Posted: Thu Jan 19, 2006 6:45 am |
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| Code: | int8 bit_position,port_value;
port_value=input_b();
printf("Input-Status PortB is ");
for (bit_position=8;bit_position>0;bit_position--) {
if (port_value & 0b10000000) putc('1');
else putc('0');
port_value<<=1;
}
putc(13); //carriage return character alias END OF LINE
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christoph
Guest
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| Posted: Thu Jan 19, 2006 8:47 am |
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thank you... this is the way i tried!
with your code it is "more careful" |
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