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Odd result for capturing duty cycle with TIMER_1 and #int_RB

 
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Harry Mueller



Joined: 17 Oct 2005
Posts: 116

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Odd result for capturing duty cycle with TIMER_1 and #int_RB
PostPosted: Thu Apr 13, 2006 12:33 pm     Reply with quote

I'm trying to develop a program that will calculate the duty cycle of an ADXL202E accelerometer on an 16F877 PIN_B7 using #int_RB. Here's the code of the interrupt service routine.
Code:


#int_RB

void accelerometer_isr(void)
{
reading = get_timer1();                     //Read Timer_1
current_portb = input_b();                  //Read value of PORT_B
delta_portb = current_portb ^ last_portb;   //Did PORT_B change?
last_portb = current_portb;                 //Remember PORT_B value
if (delta_portb = 0x80 || 0xc0)             //If PIN_B7 has changed
{
if (bit_test(current_portb, 7))             //If PIN_B7 is high
 {
  period = reading - old_reading;           //Calculate period
  old_reading = reading;
 }
 else
  duty = reading - old_reading;             //Calculate duty
 }
else;
}


When I run the program I consistently get values of around 5200 for the
period, while values for duty vary between 3 values; 2380, 2675 and 4950.

I've checked the output of PIN_B7 with an old analog scope and the value of 2380 seems to be the right one.

Any ideas on what might be happening here?

Thanks, Harry
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Thu Apr 13, 2006 12:42 pm     Reply with quote

Fix the line in bold. Look at both operators in it. Look at the logic.
Quote:
#int_RB

void accelerometer_isr(void)
{
reading = get_timer1(); //Read Timer_1
current_portb = input_b(); //Read value of PORT_B
delta_portb = current_portb ^ last_portb; //Did PORT_B change?
last_portb = current_portb; //Remember PORT_B value
if (delta_portb = 0x80 || 0xc0) //If PIN_B7 has changed
{
if (bit_test(current_portb, 7)) //If PIN_B7 is high
{
period = reading - old_reading; //Calculate period
old_reading = reading;
}
else
duty = reading - old_reading; //Calculate duty
}
else;
}
Harry Mueller



Joined: 17 Oct 2005
Posts: 116

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PostPosted: Thu Apr 13, 2006 1:27 pm     Reply with quote

[quote="PCM programmer"]Fix the line in bold. Look at both operators in it. Look at the logic.
Quote:

if (delta_portb = 0x80 || 0xc0) //If PIN_B7 has changed


I tried changing the line to:
Code:
if ((delta_portb = 0x80) || (delta_portb = 0xc0))


I think that provides the correct logic (my mind seems to rebel at this stuff) but the output hasn't changed.
newguy



Joined: 24 Jun 2004
Posts: 1909

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PostPosted: Thu Apr 13, 2006 1:31 pm     Reply with quote

Tests inside an if statement need two equal signs (==). One equal means "assign this value to the variable." Then the if sees if the variable is a 1 (true) and executes if it is.
Harry Mueller



Joined: 17 Oct 2005
Posts: 116

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PostPosted: Thu Apr 13, 2006 2:06 pm     Reply with quote

Thanks guys, that fixed it. I think I understand the "=" vs "==" better too.

Harry
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