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Alyn P.
Joined: 01 Aug 2011
Posts: 5
Location: U.K.
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| interrupt(s) sleep/wake on 12f629 an appeal! to betters |
 Posted: Tue Aug 02, 2011 5:12 am |
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Hello,
I am a new member, but I am ok with the lowly PIC 12f509. Trying to get to grips with 12f629 as its more versatile, ie interrupts. I have 'devised' a programme but unsure as to the correct syntax and proper positioning of what I want it to do. Basically at introduction of power it flashes a led (which seems to just stay on) in order to tell me power is present. Then supposed to 'go to sleep' and wait for a trigger event, go through another led flash routine, go to sleep and wait for another trigger event (on a different pin) and go through another routine! thus there are two interrupts required at different times. Sleep is important as its a power issue.
I have tried a multitude of permutations and spent an inordinate amount of time trying to teach myself, I really have run out of anymore angles- methinks the more experienced will spot my feeble efforts and put me straight please (and to shame), I will take any flack and bow to betters.
Please see following
| Code: |
#include <12F629.h>
#define GP0 PIN_A0 // define GP pins
#define GP1 PIN_A1
#define GP2 PIN_A2
#define GP3 PIN_A3
#define GP4 PIN_A4
#define GP5 PIN_A5
#define INT_GP0 0x0010B08
#define INT_GP3 0x0080B08
#define Int_Ext1 GP3
#define Int_Ext GP0
#use delay (clock=4000000) // oscillator frequency for delay_ms()
// Config: ext reset, no code protect, no watchdog, 4MHz int clock,internal rc osc no clockout
#fuses NOMCLR,NOPROTECT,NOBROWNOUT,NOWDT,INTRC_IO,
//Initialisation
void Int_Ext_isr(void)
{
input(GP0);
}
void Int_Ext1_isr(void)
{
input(GP3);
}
void Main(void)
{
output_high(GP5); //flash led
delay_ms (6000);
output_low (GP5);
// configure timer0: timer mode, prescale = 256 (increment every 256us)
setup_timer_0(RTCC_INTERNAL|RTCC_DIV_256);
setup_timer_1(T1_DISABLED);
delay_ms(100);
Ext_Int_Edge(H_To_L); //set up interrupts
Enable_Interrupts(Int_Ext);
Enable_Interrupts(Int_Ext1);
Enable_Interrupts(Global);
delay_ms(100);
sleep();
delay_ms(100);
while (input(GP0)==1); //wake up on pushbutton press
{
output_high(GP2); //flash leds
delay_ms (6000);
output_low (GP2);
delay_ms(100);
output_high(GP1);
delay_ms (6000);
output_low (GP1);
delay_ms(100);
sleep();
delay_ms(100);
}
while (input(GP3)==1); //wake up on pushbutton press
{
output_high(GP1);
delay_ms (6000);
output_low (GP1);
}} |
_________________
Al |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue Aug 02, 2011 12:40 pm |
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Here's an example of how to do an interrupt-on-change on one pin:
http://www.ccsinfo.com/forum/viewtopic.php?t=39835&start=3
That example expects you to have an external circuit on Pin A4 that
looks like this:
| Code: |
+5v
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<
> 4.7K
< ___ Switch
To | _|_|_
PIC -----------------o o------
pin GP4 |
--- GND
-
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Instead of using the external pull-up resistor, you could enable
the internal weak pull-up resistor inside the PIC for that pin.
To do this, put this line near the beginning of main():
| Code: |
port_a_pullups(0x10); // Enable internal pull-up on pin GP4
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Note that pin GP3 does not have an internal pull-up available. It must
have an external pull-up added to the pin, as shown in the schematic above.
Also note that the #int_ra interrupt-on-change interrupt is different than
the #int_ext interrupt. |
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Alyn P.
Joined: 01 Aug 2011
Posts: 5
Location: U.K.
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| Posted: Tue Aug 02, 2011 3:45 pm |
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thanks for the info, all information is more than greatly received for anyone giving the code more scrutiny! to get it to run/at all.
_________________
Al |
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