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pic18f4431 with adc

 
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deenadayalan



Joined: 19 Oct 2013
Posts: 19
Location: salam

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pic18f4431 with adc
PostPosted: Wed Sep 10, 2014 11:28 pm     Reply with quote

dear all, i am using pic18f4431 controller. I am using adc channel pin a0. I got 255 only in serial window through hardware crystal value 20mhz. Pls help me dear all

i initialized like
Code:
void main()
{
unsigned int valadc=0;

set_tris_a(0x1f);
setup_adc_ports(sAN0|VSS_VDD);
setup_adc(ADC_CLOCK_INTERNAL|ADC_TAD_MUL_0|ADC_WHEN_INT0|ADC_INT_EVERY_OTHER);
setup_timer_0(RTCC_INTERNAL);

set_adc_channel(0);

  while(true)
    {
     delay_ms(100);
     valadc = read_adc();
     valadc=valadc*0.0197;
     printf("\n\r");
     printf("%u",valadc);
    }
}

Code:
/*************header file***************/

#include <18F4431.h>
#device adc=8

#FUSES NOWDT                    //No Watch Dog Timer
#FUSES WDT128                   //Watch Dog Timer uses 1:128 Postscale
#FUSES HS                       //High speed Osc (> 4mhz)
#FUSES NOPROTECT                //Code not protected from reading
#FUSES NOIESO                   //Internal External Switch Over mode disabled
#FUSES NOBROWNOUT               //No brownout reset
#FUSES BORV27                   //Brownout reset at 2.7V
#FUSES NOPUT                    //No Power Up Timer
#FUSES NOCPD                    //No EE protection
#FUSES STVREN                   //Stack full/underflow will cause reset
#FUSES NODEBUG                  //No Debug mode for ICD
#FUSES NOLVP                      //Low Voltage Programming on B3(PIC16) or B5(PIC18)
#FUSES NOWRT                    //Program memory not write protected
#FUSES NOWRTD                   //Data EEPROM not write protected
#FUSES FCMEN                    //Fail-safe clock monitor enabled
#FUSES NOWINEN                  //WDT Timer Window Disabled
#FUSES T1LOWPOWER               //Timer1 low power operation when in sleep
#FUSES HPOL_HIGH                //High-Side Transistors Polarity is Active-High (PWM 1,3,5 and 7)
   //PWM module high side output pins have active high output polarity
#FUSES NOWRTC                   //configuration not registers write protected
#FUSES NOWRTB                   //Boot block not write protected
#FUSES NOEBTR                   //Memory not protected from table reads
#FUSES NOEBTRB                  //Boot block not protected from table reads
#FUSES NOCPB                    //No Boot Block code protection
#FUSES LPOL_HIGH                //Low-Side Transistors Polarity is Active-High (PWM 0,2,4 and 6)
   //PWM module low side output pins have active high output polar
#FUSES PWMPIN                   //PWM outputs disabled upon Reset
#FUSES MCLR                     //Master Clear pin enabled
#FUSES FLTAC1                   //FLTA input is multiplexed with RC1
#FUSES SSP_RC                   //SCK/SCL=RC5, SDA/SDI=RC4, SDO=RC7
#FUSES PWM4B5                   //PWM4 output is multiplexed on RB5
#FUSES EXCLKC3                  //TMR0/T5CKI external clock input is muliplexed with RC3

#use delay(clock=20000000)
#use rs232(baud=9600,parity=N,xmit=PIN_C6,rcv=PIN_C7,bits=8)

Rolling Eyes
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Thu Sep 11, 2014 12:22 am     Reply with quote

Three reasons one after the other:

adc=8

tells the compiler to only read the 8bit value from the adc....

Then:

unsigned int valadc=0;

How big is an int?.

Then:

printf("%u",valadc);

What size variables can %u handle?. Look at what %Lu handles instead.

Each of these will stop you getting the 10bit value.
deenadayalan



Joined: 19 Oct 2013
Posts: 19
Location: salam

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PostPosted: Thu Sep 11, 2014 1:32 am     Reply with quote

8 bit adc enough this application sir , i used int but simulation showed negative values ,if i use unsigned int and %u simulation showed 0 to 255
properly ,i checked in a0 pin during the adc input,voltage reaching in a0 but i got 255 only in output window

this is my problem sir
Ttelmah



Joined: 11 Mar 2010
Posts: 19538

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PostPosted: Thu Sep 11, 2014 1:45 am     Reply with quote

Er....

An 8bit value, has 256 values. 0 to 255. 255, is the biggest value that the ADC can return in 8bit mode, and the biggest value that an int8 can hold.
deenadayalan



Joined: 19 Oct 2013
Posts: 19
Location: salam

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PostPosted: Thu Sep 11, 2014 2:32 am     Reply with quote

even i am connecting adc to gnd result is 255 sir didn't show 0
deenadayalan



Joined: 19 Oct 2013
Posts: 19
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PostPosted: Thu Sep 11, 2014 2:38 am     Reply with quote

this code also showed same result,result 03ff didnt change any analog input


Code:
#include <18F4431.h>
#device adc=10
#fuses HS,NOWDT,NOPROTECT,BROWNOUT,PUT,NOLVP
#use delay(clock=20000000) 
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)

//=================================
void main()
{
int16 result;

setup_adc_ports(sAN0);
setup_adc(ADC_CLOCK_DIV_32);
set_adc_channel(0);
delay_us(15);

while(1)
  { 
   result = read_adc();
   printf("%LX \n\r", result);
   delay_ms(500);
  }

}
rikotech8



Joined: 10 Dec 2011
Posts: 376
Location: Sofiq,Bulgariq

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PostPosted: Thu Sep 11, 2014 2:39 am     Reply with quote

Valadc = valadc * 0,0197
The right side of the equation returns a floating point since the 0,0197 is such format.
Then you asaign it to an unint. It is uncorrect.
_________________
A person who never made a mistake never tried anything new.
deenadayalan



Joined: 19 Oct 2013
Posts: 19
Location: salam

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PostPosted: Thu Sep 11, 2014 2:45 am     Reply with quote

thank you dear rikotech8 , i am getting same problem another attached example. i couldnt find my mistake
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Thu Sep 11, 2014 3:04 am     Reply with quote

Well you are telling the ADC to sample on an interrupt....

Just look in the forum, at code people use for the ADC. Your setup, is _not_ how to use the adc.

An int, is unsigned by default.

What changes how it is displayed, is the format in the printf statement. %d, prints it as a signed value, %u prints it as an unsigned.

Your maths is completely screwed. The int, can't hold the result in any meaningful manner.....
Code:

void main()
{
   int8 valadc;

   setup_adc_ports(sAN0|VSS_VDD);
   setup_adc(ADC_CLOCK_INTERNAL); //OK for 8bit, but not recommended
   set_adc_channel(0); //voltage input on pin2.

   while(true)
   {
      delay_ms(100);
      valadc = read_adc();
      valadc=(valadc * 10L) / 51; //at this point the multiply needs 16bit. 'L'
      printf("\n\r%3.1w volts",valadc); //display as x.x volts
    }
}


As a general comment, add 'ERRORS' to your RS232 declaration.

ERRORS, is _required_ when using hardware RS232, unless _you_ handle the error conditions yourself. It is a problem waiting to catch you, unless you use it.
deenadayalan



Joined: 19 Oct 2013
Posts: 19
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PostPosted: Thu Sep 11, 2014 3:35 am     Reply with quote

thank you dear Ttelmah i got continuously 5.0 volts, i used your code, again thank you for your valuable code, i used 20mhz crystal 22pf capacitor in my hardware circuit.
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Thu Sep 11, 2014 3:47 am     Reply with quote

Seriously I'd bet pin 2 is shorted high.
deenadayalan



Joined: 19 Oct 2013
Posts: 19
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PostPosted: Thu Sep 11, 2014 4:01 am     Reply with quote

sir i checked normally it has 0.8 v
when connected variable resistor for adc input

adc v --------------- controller pin (v)

starting -------------- 0.004

middle --------------- 2.505

ending ------------ 5
deenadayalan



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Posts: 19
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PostPosted: Thu Sep 11, 2014 6:50 am     Reply with quote

dear all i changed crystal value (16mhz) . i got perfect output thank you very much sir................ Very Happy Very Happy Very Happy Very Happy Very Happy Very Happy
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