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yo4hsp
Joined: 12 Sep 2008
Posts: 7
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| How to convert bin to hex, hex to bin |
 Posted: Tue Oct 27, 2009 12:00 am |
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Hello,
I need to convert 16 bits Bin code(2) to 2 bytes Hexa (from an AD converter), then this 2bytes in Hexa(16) I need to convert to 12 bits Bin code (2). (for DA converter).
The problem is with my numbers: negatives and decimal like: -0.1234 (in dec)...
Thanks, |
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bungee-
Joined: 27 Jun 2007
Posts: 206
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| Posted: Tue Oct 27, 2009 2:05 am |
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Why do you need to convert to the HEX in the first place? 
Data you supplied is not enough to adequately help you. |
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Wayne_
Joined: 10 Oct 2007
Posts: 681
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| Posted: Tue Oct 27, 2009 3:32 am |
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So you are reading a 16 bit value from an A2D and you need to convert that to a 12 bit value to output on your D2A !
The value, although stored as binary does not need converting! HEX and Decimal for that matter are just representations of the same value.
So 01100011 (binary) = 0x63 (hex) = 99 (decimal). No conversion, they just are those values.
What we need to know is what your A2D is reading in and what you are trying to control using the D2A.
You then need a formula to convert the 16 bit value to an appropriate 12 bit value. |
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yo4hsp
Joined: 12 Sep 2008
Posts: 7
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| hex to bin, bin to hex |
| Posted: Sun Nov 01, 2009 11:57 am |
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ok, this is my code:
| Code: |
int8 bin_to_hex (int bin)
{
int8 hex;
if ( bin == 0000) hex = 0x0;
if ( bin == 0001) hex = 0x1;
if ( bin == 0010) hex = 0x2;
if ( bin == 0011) hex = 0x3;
if ( bin == 0100) hex = 0x4;
if ( bin == 0101) hex = 0x5;
if ( bin == 0110) hex = 0x6;
if ( bin == 0111) hex = 0x7;
if ( bin == 1000) hex = 0x8;
if ( bin == 1001) hex = 0x9;
if ( bin == 1010) hex = 0xA;
if ( bin == 1011) hex = 0xB;
if ( bin == 1100) hex = 0xC;
if ( bin == 1101) hex = 0xD;
if ( bin == 1110) hex = 0xE;
if ( bin == 1111) hex = 0xF;
else hex = 0x0;
return hex;
} |
and the second,
| Code: |
int8 hex_to_bin (int hex)
{
int8 bin;
if (hex == 0x0) bin = 0000;
if (hex == 0x1) bin = 0001;
if (hex == 0x2) bin = 0010;
if (hex == 0x3) bin = 0011;
if (hex == 0x4) bin = 0100;
if (hex == 0x5) bin = 0101;
if (hex == 0x6) bin = 0110;
if (hex == 0x7) bin = 0111;
if (hex == 0x8) bin = 1000;
if (hex == 0x9) bin = 1001;
if (hex == 0xA) bin = 1010;
if (hex == 0xB) bin = 1011;
if (hex == 0xC) bin = 1100;
if (hex == 0xD) bin = 1101;
if (hex == 0xE) bin = 1110;
if (hex == 0xF) bin = 1111;
else bin = 0000;
return bin;
} |
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yo4hsp
Joined: 12 Sep 2008
Posts: 7
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| re.. |
| Posted: Sun Nov 01, 2009 12:00 pm |
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| I used ADC - ads8321 (16bit) and DAC max531. The read value from ADC is applied to a FIR filter with 31 coef, then send to DAC... |
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FvM
Joined: 27 Aug 2008
Posts: 2337
Location: Germany
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| Posted: Sun Nov 01, 2009 2:29 pm |
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I'm almost helpless with your code.
E.g.
if (hex == 0xF) bin = 1111;
1111 means in words eleven hundred - eleven
After assigning the constant to int8, you get bin = 87, due to overflow |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Sun Nov 01, 2009 2:37 pm |
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Try to find some web pages that explain number representation in C
in a simple way. Example:
http://www.codeguru.com/forum/showthread.php?t=316299
Based on your description, you really just need a simple program
as shown below.
| Code: |
#include <16F877.H>
#fuses XT, NOWDT, BROWNOUT, PUT, NOLVP
#use delay(clock=4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)
#include "ads8321.c"
#include "FIR_filter.c"
#include "max5321.c"
//======================================
void main()
{
int16 adc_value;
int16 result;
adc_value = read_ads8321(); // Read ADC value
result = FIR_filter(adc_value); // Filter it
write_max5321(result); // Write it to DAC
while(1);
}
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