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seifpic
Joined: 11 Mar 2012
Posts: 45
Location: Egypt
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| [Answered] Out of Rom Pic16F628A |
 Posted: Sun Mar 11, 2012 3:28 pm |
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I am making a digital clock using LEDs powered by shift registers instead of a 7 segment display. Anyway, when compiling the code, I get the following error:
| Code: | ***Error 71 "test.c" Line 351(0,1) Out of ROM, A segment or the program is too large num
Seg 00004-007FF, 07DC left, need 0F8F
Seg 00000-00003, 0000 left, need 0F8F |
And here is my code so far:
| Code: |
#include <16f628a.h>
#use delay (crystal=32768)
void num(int rnum, char out, char clk) {
//start clear shift register
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
//end clear shift register
switch(rnum) {
case 0:
output_high(out);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_low(out);
break;
case 1:
output_low(out);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
break;
case 2:
output_high(out);//7
output_high(clk);
output_low(clk);
output_low(out);//6
output_high(clk);
output_low(clk);
output_high(out);//5
output_high(clk);
output_low(clk);
output_high(clk);//4
output_low(clk);
output_high(clk);//3
output_low(clk);
output_low(out);//2
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
break;
case 3:
output_high(out);//7
output_high(clk);
output_low(clk);
output_high(clk);//6
output_low(clk);
output_high(clk);//5
output_low(clk);
output_low(out);//4
output_high(clk);
output_low(clk);
output_high(out);//3
output_high(clk);
output_low(clk);
output_low(out);//2
output_high(clk);
output_low(clk);
output_high(out);//1
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
break;
case 4:
output_high(out);//7
output_high(clk);
output_low(clk);
output_high(out);//6
output_high(clk);
output_low(clk);
output_low(out);//5
output_high(clk);
output_low(clk);
output_low(out);//4
output_high(clk);
output_low(clk);
output_high(out);//3
output_high(clk);
output_low(clk);
output_high(out);//2
output_high(clk);
output_low(clk);
output_low(out);//1
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
break;
case 5:
output_low(out);//7
output_high(clk);
output_low(clk);
output_high(out);//6
output_high(clk);
output_low(clk);
output_high(out);//5
output_high(clk);
output_low(clk);
output_low(out);//4
output_high(clk);
output_low(clk);
output_high(out);//3
output_high(clk);
output_low(clk);
output_high(out);//2
output_high(clk);
output_low(clk);
output_high(out);//1
output_high(clk);
output_low(clk);
output_low(out);//reset
output_high(clk);
output_low(clk);
break;
case 6:
output_low(out);//7
output_high(clk);
output_low(clk);
output_high(out);//6
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);//reset
output_high(clk);
output_low(clk);
break;
case 7:
output_high(out);//7
output_high(clk);
output_low(clk);
output_high(clk);//6
output_low(clk);
output_low(out);//5
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(out);//1
output_high(clk);
output_low(clk);
output_low(out);//reset
output_high(clk);
output_low(clk);
break;
case 8:
output_high(out);//7
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);//reset
output_high(clk);
output_low(clk);
break;
case 9:
output_high(out);//7
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);//4
output_high(clk);
output_low(clk);
output_high(out);//3
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);//reset
output_high(clk);
output_low(clk);
break;
case 10:
output_high(out);
output_high(clk);//7
output_low(clk);
output_high(clk);//6
output_low(clk);
output_high(clk);//5
output_low(clk);
output_high(clk);//4
output_low(clk);
output_low(out);//3 l
output_high(clk);//3
output_low(clk);
output_high(out);//2 h
output_high(clk);//2
output_low(clk);
output_high(clk);//1
output_low(clk);
output_high(clk);
output_low(clk);
output_low(out);
break;
case 11:
output_low(out);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
break;
case 12:
output_high(out);//7
output_high(clk);
output_low(clk);
output_low(out);//6
output_high(clk);
output_low(clk);
output_high(out);//5
output_high(clk);
output_low(clk);
output_high(clk);//4
output_low(clk);
output_high(clk);//3
output_low(clk);
output_low(out);//2
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_high(out);
output_high(clk);
output_low(clk);
output_low(out);
break;
}
}
//==============================
void main() {
int i;
while(true) {
for(i=1;i<10;++i) {
num(i, pin_a1, pin_a0);
delay_ms(2000);
}
i=0;
}
}
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can somebody please help me with this problem regarding that I'm a newbie to this subject?
Thanks in advance.
Last edited by seifpic on Sun Mar 11, 2012 5:45 pm; edited 2 times in total |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Sun Mar 11, 2012 3:31 pm |
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Get a book on the C language or just Google for this:
| Quote: |
C tutorial for loops
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And one more tip: Don't use floating point in a small PIC. |
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seifpic
Joined: 11 Mar 2012
Posts: 45
Location: Egypt
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| Posted: Sun Mar 11, 2012 3:34 pm |
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| PCM programmer wrote: | Get a book on the C language or just Google for this:
| Quote: |
C tutorial for loops
|
And one more tip: Don't use floating point in a small PIC. |
Ok, I know I did the loop in the main function in a hideous way but my question was about the Out of ROM error. I also forgot to mention I'm new to this subject so I didn't understand your tip. |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19544
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| Posted: Sun Mar 11, 2012 3:39 pm |
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A search of the forum would find the answer.
Key point is that the PIC memory, is organised as a number of small pages, and each subroutine has to fit into a page.
You have 99% of your code in one enormous 'lump', which can't be split up.
Most of the sequences of high/low clocks, could be made into a single routine, and then called, rather than being repeated again and again in the code.....
Best Wishes |
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seifpic
Joined: 11 Mar 2012
Posts: 45
Location: Egypt
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| Posted: Sun Mar 11, 2012 3:43 pm |
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| Ttelmah wrote: | A search of the forum would find the answer.
Key point is that the PIC memory, is organised as a number of small pages, and each subroutine has to fit into a page.
You have 99% of your code in one enormous 'lump', which can't be split up.
Most of the sequences of high/low clocks, could be made into a single routine, and then called, rather than being repeated again and again in the code.....
Best Wishes |
Your reply gave me an idea, the numbers' segments could be stored as an array of bits which is called in a function that has the routine. Could that work? |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19544
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| Posted: Mon Mar 12, 2012 3:00 am |
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Even simpler an array of bytes.
For instance (hypothetical only):
| Code: |
const int8 patterns[] = {0b00101011,0b11001100,.....};
void send_pattern(int8 pattern_number) {
int8 count, temp,mask=1;
temp=patterns[pattern_number]; //Get the selected pattern to send
for (count=0;count<8;count++) {
output_high(clk);
output_low(clk);
}
//much smaller than doing this eight times.....
for (count=0;count<8;count++) {
output_bit(out,temp&mask); //output bit
output_high(clk);
mask<<=1; //rotate mask
output_low(clk);
}
//Then send 'patterns[pattern_number]'
}
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This sends the bits LSb first - alternatively start with mask=128, and shift it right to send the bits MSb first.
Hopefully you get the idea.
Your cases would then disappear, and just become a single call to send_pattern, with rnum being the pattern to send.
Code many times smaller...
Best Wishes |
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