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Dividend not work v5.021 SOLVED

 
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Eddy71ua



Joined: 23 Sep 2009
Posts: 55
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Dividend not work v5.021 SOLVED
PostPosted: Sun Mar 09, 2014 7:51 am     Reply with quote

I try this: Tmp16 = (int16)(Tmp16 / 100);

And get this:
Code:

....................       
00F7:  MOVF   59,W
00F8:  MOVWF  5B
00F9:  MOVF   58,W
00FA:  MOVWF  5A
00FB:  CLRF   5D
00FC:  MOVLW  64
00FD:  MOVWF  5C
*
0122:  MOVF   22,W
0123:  MOVWF  59
0124:  MOVF   21,W
0125:  MOVWF  58


Function not work?


Last edited by Eddy71ua on Mon Mar 10, 2014 3:42 am; edited 1 time in total
temtronic



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PostPosted: Sun Mar 09, 2014 9:30 am     Reply with quote

You really need to post a short, compilable program that shows the problem!
Posting 11 lines of assembler just doesn't show us what is going on or HOW it was created.

hth
jay
Ttelmah



Joined: 11 Mar 2010
Posts: 19539

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PostPosted: Sun Mar 09, 2014 12:02 pm     Reply with quote

In the include file for the processor, rem out the line near the top 'nolist'. Recompile. You will suddenly find that the code for internal functions like division will appear in the listing. Currently the actual division is the '*' part....

Test with a simple test using printf.

Print Tmp16. Then divide it, and print the result.

Your cast does nothing. Tmp16 is already an int16, and as such the result from the sum will be an int16. I'd suspect your actual problem is somewhere else with what is in the variable or what you 'expect'. Remember 99/100 for example will give 0.

Best Wishes
Eddy71ua



Joined: 23 Sep 2009
Posts: 55
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PostPosted: Mon Mar 10, 2014 2:39 am     Reply with quote

Quote:
In the include file for the processor, rem out the line near the top 'nolist'. Recompile.


I do this:

Code:

#device PIC16F676
//#nolist
//////// Program memory: 1024x14  Data RAM: 64  Stack: 8


Quote:
Recompile. You will suddenly find that the code for internal functions like division will appear in the listing. Currently the actual division is the '*' part....


Okay..

Code:

....................       Tmp16 = Tmp16 + 50;
00F3:  MOVLW  32
00F4:  ADDWF  58,F
00F5:  BTFSC  03.0
00F6:  INCF   59,F
....................       Tmp16 = (int16)(Tmp16 / 100);
00F7:  MOVF   59,W
00F8:  MOVWF  5B
00F9:  MOVF   58,W
00FA:  MOVWF  5A
00FB:  CLRF   5D
00FC:  MOVLW  64
00FD:  MOVWF  5C
*
0122:  MOVF   22,W
0123:  MOVWF  59
0124:  MOVF   21,W
0125:  MOVWF  58


Any changes..


Quote:
Test with a simple test using printf.

Print Tmp16. Then divide it, and print the result.


First did so, I found the problem and wrote on the forum.

After dividing the 16-bit number (0 - 10000, not more than) / 100, I get a rezult number 0-1-2.

Code:

int8 SensorLvl, TriggerLevel;
int16 Tmp16;

Tmp16 = (int16)(SensorLvl * 43);
Tmp16 = Tmp16 + 50;
Tmp16 = (int16)(Tmp16 / 100);
TriggerLevel = make8(Tmp16,0);


SensorLvl and TriggerLevel is global variables.
Ttelmah



Joined: 11 Mar 2010
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PostPosted: Mon Mar 10, 2014 2:45 am     Reply with quote

Your casting is wrong:
Code:

Tmp16 = (int16)(SensorLvl * 43);


SensorLyl is an int8.
So is '43'.
So the multiplication is done using int8 arithmetic.

You then cast the int8 _result_ to int16.

You need:
Code:

Tmp16 = (int16)SensorLvl * 43;
//or

Tmp16 = SensorLvl * 43L;


The first converts SensorLvl to an int16 _before_ the multiplication, so int16 arithmetic is used. The second tells the compiler to treat '43' as an int16, so again int16 arithmetic is used.

Again the cast on your division is 'pointless'. Tmp16 is already an int16.

Brackets mean (effectively), 'do what is inside first'. So your layout does the multiplication 'first', then casts the result. But you need to do the cast _first_.
Eddy71ua



Joined: 23 Sep 2009
Posts: 55
Location: Ukraine

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PostPosted: Mon Mar 10, 2014 3:40 am     Reply with quote

Thanks, you're right, I was wrong. Thank you very much for your help! Laughing
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