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How to copy array from ROM in RAM ?

 
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Mike.B



Joined: 04 Aug 2014
Posts: 5

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How to copy array from ROM in RAM ?
PostPosted: Mon Aug 04, 2014 9:38 am     Reply with quote
Hello !

I have just bought a PICKIT3 from Microchip (my first PIC !) and I have got problems with my code.
My goal : copy values from an array in ROM into an array in RAM.

Here is my code :

Code:
#include <18F45K20.h>

const int array1[8]={7,8,9,10,15,14,12,22};
int array2[8];

void main(){
   int i=0;
   for(i=0;i<8;i++){
      array2[i]=array1[i];
   }
}


This code works ! All values from array1 are in array2.

Now, I want to do the same thing but I would like to use a function.

Here is my new code :


Code:

#include <18F45K20.h>

const int array1[8]={7,8,9,10,15,14,12,22};
int array2[8];

void transfer(const int array1[8], int array2[8]){
   int i=0;
   for(i=0;i<8;i++){
      array2[i]=array1[i];
   }
}

void main(){
   transfer(array1,array2);
   
}


Unfortunately, it doesn't work.
Here are my errors :

Code:
*** Error 28 "main.c" Line 6(25,28): Expecting an identifier
*** Error 43 "main.c" Line 6(31,32): Expecting a declaration
*** Error 43 "main.c" Line 6(32,33): Expecting a declaration
*** Error 43 "main.c" Line 6(33,34): Expecting a declaration
*** Error 43 "main.c" Line 6(34,35): Expecting a declaration
--- Info 300 "main.c" Line 4(5,11): More info:   First Declaration of array2
*** Error 31 "main.c" Line 6(40,46): Identifier is already used in this scope
*** Error 43 "main.c" Line 6(47,48): Expecting a declaration
*** Error 43 "main.c" Line 6(48,49): Expecting a declaration
*** Error 43 "main.c" Line 6(49,50): Expecting a declaration
*** Error 43 "main.c" Line 6(50,51): Expecting a declaration
*** Error 43 "main.c" Line 8(1,4): Expecting a declaration
*** Error 43 "main.c" Line 8(4,5): Expecting a declaration
*** Error 48 "main.c" Line 8(5,6): Expecting a (
*** Error 43 "main.c" Line 8(7,8): Expecting a declaration
*** Error 43 "main.c" Line 8(8,9): Expecting a declaration
*** Error 48 "main.c" Line 8(9,10): Expecting a (
*** Error 43 "main.c" Line 8(11,12): Expecting a declaration
*** Error 43 "main.c" Line 8(12,13): Expecting a declaration
*** Error 48 "main.c" Line 8(13,14): Expecting a (
*** Error 43 "main.c" Line 8(16,17): Expecting a declaration
*** Error 43 "main.c" Line 8(17,18): Expecting a declaration
*** Error 48 "main.c" Line 9(1,7): Expecting a (
*** Error 48 "main.c" Line 9(8,9): Expecting a (
*** Error 43 "main.c" Line 9(10,11): Expecting a declaration
*** Error 48 "main.c" Line 9(11,17): Expecting a (
*** Error 48 "main.c" Line 9(18,19): Expecting a (
*** Error 43 "main.c" Line 9(20,21): Expecting a declaration
*** Error 43 "main.c" Line 10(1,2): Expecting a declaration
*** Error 43 "main.c" Line 11(1,2): Expecting a declaration
*** Error 58 "main.c" Line 14(10,16): Expecting a close paren



How can I fix that ?

Thank you very much and have a nice day !
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Mon Aug 04, 2014 11:42 am     Reply with quote
This revised version works. It displays the following in the MPLAB
simulator output window:
Quote:
7 8 9 10 15 14 12 22

This was tested with compiler vs. 5.026.
Code:

#include <18F45K20.h>
#device PASS_STRINGS=IN_RAM
#fuses INTRC_IO, BROWNOUT, PUT, NOWDT
#use delay(clock=4M)
#use rs232(baud=9600, UART1, ERRORS)

const int8 array1[8]={7,8,9,10,15,14,12,22};
int8 array2[8];

void transfer(int8 array1[], int8 array2[])
{
 int8 i=0;
 
 for(i=0;i<8;i++)
    {
     array2[i]=array1[i];
    }
}

//==========================
void main()
{
int8 i;

transfer(array1,array2);

 for(i=0;i<8;i++)
    {
     printf("%d ", array2[i]);
    }

printf("\r");

while(1);   
}
Mike.B



Joined: 04 Aug 2014
Posts: 5

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PostPosted: Mon Aug 04, 2014 1:39 pm     Reply with quote
Hello PCM programmer !

Thank you for your help, it's nice.
It works perfectly !
Just a little question, I use to monitor my values via the WATCH. You seem to use RS232. Where do you display your values ?
In the MPLAB simulator output window, I have got nothing.

Thanks
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Mon Aug 04, 2014 1:49 pm     Reply with quote
I still mostly use MPLAB vs. 8.92, so the following instructions apply to
that version. This link tells how to display UART output in MPLAB simulator:
http://www.ccsinfo.com/forum/viewtopic.php?t=23408&start=1
Mike.B



Joined: 04 Aug 2014
Posts: 5

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PostPosted: Mon Aug 04, 2014 2:46 pm     Reply with quote
Alright, thank you ! I didn't know we could do that.

Now, I would like to do the same thing but I would like to use matrix instead of array.

I use your code and try to adapt it. However, it doesn't work.
Here is the code :



Code:

-----------

#include <18F45K20.h>
#device PASS_STRINGS=IN_RAM
#fuses INTRC_IO, BROWNOUT, PUT, NOWDT
#use delay(clock=4M)
#use rs232(baud=9600, UART1, ERRORS)

const int8 matrix1[3][2]={{1,1},{1,1},{2,2}};
int8 matrix2[3][2];

void transfer(int8 m1[][], int8 m2[][])
{
 int8 i=0;
 int8 j=0;
 
for(j=0;j<2;j++){ 
 for(i=0;i<3;i++)
    {
     m2[i][j]=m1[i][j];
    }
}
}

//==========================
void main()
{
int8 i;
int8 j;

transfer(matrix1,matrix2);

for(j=0;j<2;j++){
 for(i=0;i<8;i++)
    {
     printf("%d ", matrix2[i][j]);
    }
}

printf("\r");

while(1);   
}


I don't understand where is the problem because I have just done a few modifications.
What do you think ?
Maybe I should seek about pointer (I am going to look for more information about it because it's new to me)

Thanks for your help
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Mon Aug 04, 2014 3:08 pm     Reply with quote
I'm tied up for the next 2-3 hours. If nobody else helps you, when I come
back I'll look at the problem.
luckyluke



Joined: 18 Apr 2006
Posts: 45

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PostPosted: Mon Aug 04, 2014 3:38 pm     Reply with quote
Quote:
for(i=0;i<8;i++)
Mike.B



Joined: 04 Aug 2014
Posts: 5

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PostPosted: Mon Aug 04, 2014 3:46 pm     Reply with quote
Alright, no problem, I understand Very Happy

As for me, I am keep seeking.
Actually, I think I succeeded by using pointers.

I have read this statement :
int matrix[nb_rows][nb_columns] is equivalent to int *(matrix + (nb_columns * rows) + columns)

I have admitted that (I know it is bad...)

Here is my code :

Code:
#include <18F45K20.h>
#device PASS_STRINGS=IN_RAM
#fuses INTRC_IO, BROWNOUT, PUT, NOWDT
#use delay(clock=4M)
#use rs232(baud=9600, UART1, ERRORS)

const int8 matrix1[3][2]={{20,70},{120,110},{40,30}};
int8 matrix2[3][2]={0};

void transfer(int8 **m1, int8 **m2)
{
 int8 i=0;
 int8 j=0;
 
for(j=0;j<2;j++){ 
 for(i=0;i<3;i++)
    {
   *(m2+(1*i)+j)=*(m1+(1*i)+j);
    }
}
}

//==========================
void main()
{
int8 i;
int8 j;

transfer(matrix1,matrix2);

for(j=0;j<2;j++){
 for(i=0;i<3;i++)
    {
     printf("%d ", matrix2[i][j]);
    }
}

printf("\r");

while(1);   
}


It works !

If someone can explain me why it works and why the previous code doesn't work, it will great !
It is important to me to understand.

Thanks

Last edited by Mike.B on Mon Aug 04, 2014 3:51 pm; edited 1 time in total
Mike.B



Joined: 04 Aug 2014
Posts: 5

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PostPosted: Mon Aug 04, 2014 3:50 pm     Reply with quote
Hello luckyluke !

Thanks for answering, I have just seen it.
I will fix that.
Actually, I checked the value by using the WATCH.
So, I don't think it is the main problem. But it is a step forward Smile
luckyluke



Joined: 18 Apr 2006
Posts: 45

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PostPosted: Mon Aug 04, 2014 4:02 pm     Reply with quote
Code:

void transfer(int8 m1[][2], int8 m2[][2])
{
 int8 i=0;
 int8 j=0;
 
for(j=0;j<2;j++){ 
 for(i=0;i<3;i++)
    {
     m2[i][j]=m1[i][j];
    }
}
}

what about like this?
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