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Pointer in functions problem...

 
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micro



Joined: 10 Sep 2003
Posts: 13

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Pointer in functions problem...
PostPosted: Wed Oct 06, 2004 3:04 am     Reply with quote

Hi!,

I have some problems with using pointer in functions.
I have written a simple code snipped that use pointers but it does not work.

#include <18f458.h>
#include <string.h>
//#device *=16
#fuses H4,NOWDT,NOPROTECT,NOBROWNOUT,NOPUT,NOLVP
#use delay(clock=40000000)
#use rs232 (baud=9600, xmit=PIN_C6, rcv=PIN_C7,ERRORS)



byte WriteIntoBuff(int16 Length, unsigned char *BuffAddr)
{

int16 count;

for(count=0;count<Length;count++)
{
Buff[PT_WrIndex]=*BuffAddr;
BuffAddr++;
}
}


void main(void)
{

int16 tx_count;
unsigned char s[100];
int16 adres;
adres=&s[0];
strcpy(s,"This is a sample text string for PIC18F458 UART0 Tx test");

txcount=strlen(s);

WriteIntoPumpTxBuff(tx_count,s);

.
.
.
.

}
alexz



Joined: 17 Sep 2004
Posts: 133
Location: UK

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PostPosted: Wed Oct 06, 2004 3:37 am     Reply with quote

What exactly does not work?
Have you declare the function prototype as
byte WriteIntoBuff(int16 Length, unsigned char *BuffAddr) ;
Where do you actually call this function?
_________________
Alex
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PostPosted: Wed Oct 06, 2004 4:16 am     Reply with quote

I have made a mistake in my question. Correct code is below

#include <18f458.h>
#include <string.h>
//#device *=16
#fuses H4,NOWDT,NOPROTECT,NOBROWNOUT,NOPUT,NOLVP
#use delay(clock=40000000)
#use rs232 (baud=9600, xmit=PIN_C6, rcv=PIN_C7,ERRORS)



byte WriteIntoBuff(int16 Length, unsigned char *BuffAddr)
{

int16 count;

for(count=0;count<Length;count++)
{
Buff[PT_WrIndex]=*BuffAddr;
BuffAddr++;
}
}


void main(void)
{

int16 tx_count;
unsigned char s[100];
int16 adres;
adres=&s[0];
strcpy(s,"This is a sample text string for PIC18F458 UART0 Tx test");

txcount=strlen(s);

WriteIntoBuff(tx_count,&s[0]);

.
.
.
.

}

In the code, WriteIntoBuff does not work. It should be take "s" array and put it in to "Buff" array but it does not. What is wrong with it..?
alexz



Joined: 17 Sep 2004
Posts: 133
Location: UK

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PostPosted: Wed Oct 06, 2004 4:19 am     Reply with quote

Try to cal the function this way:
WriteIntoBuff(tx_count,s[0]);
in other words no '&', as you already pass the pointer.
_________________
Alex
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PostPosted: Wed Oct 06, 2004 4:38 am     Reply with quote

I have tried but it does not work again. Actually, a pointer variable requieres an adsress as a value. So it seems , & operator is required but it does not work. I am confused.
alexz



Joined: 17 Sep 2004
Posts: 133
Location: UK

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PostPosted: Wed Oct 06, 2004 4:43 am     Reply with quote

you definitely do not need the '&'.
Try this:

WriteIntoBuff(tx_count,s);

byte WriteIntoBuff(int16 Length, unsigned char *BuffAddr)
{

int16 count;

for(count=0;count<Length;count++)
{
Buff[PT_WrIndex]=*BuffAddr[0];
}
}

If that does not work, declare this array as global and do not pass it.
_________________
Alex
Mark



Joined: 07 Sep 2003
Posts: 2838
Location: Atlanta, GA

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PostPosted: Wed Oct 06, 2004 7:47 am     Reply with quote

Code:

Buff[PT_WrIndex]=*BuffAddr;


Umm... how about this
Code:

Buff[count]=*BuffAddr;


Quote:

WriteIntoBuff(tx_count,s[0]);
in other words no '&', as you already pass the pointer.


Please help only if you are sure of yourself. s[0] is the value of the array! You DEFINITELY need to pass the address.
Code:

WriteIntoBuff(tx_count,&s[0]);
WriteIntoBuff(tx_count,s);
treitmey



Joined: 23 Jan 2004
Posts: 1094
Location: Appleton,WI USA

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PostPosted: Wed Oct 06, 2004 8:45 am     Reply with quote

I always thought an array is the same as a pointer...

referance K&R second edition page 98 - 99.

I think passing the address of "&n[2]"
should work the same as n
when n is an array...n[5]


(if you don't know what K&R is...it shows I'm getting old)


Last edited by treitmey on Wed Oct 06, 2004 9:42 am; edited 2 times in total
alexz



Joined: 17 Sep 2004
Posts: 133
Location: UK

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PostPosted: Wed Oct 06, 2004 8:47 am     Reply with quote

Sorry, I meant no '&' when passing just the name of the array
_________________
Alex
JPA
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Pointers and array
PostPosted: Wed Oct 06, 2004 9:25 am     Reply with quote

treitmey wrote:
I always thought an array is the same as a pointer...

referance K&R second edition page 98 - 99.

I think passing the address of "&n"
should work the same as n[5]
when n is an array...n[5]


(if you don't know what K&R is...it shows I'm getting old)


When I was a student, in 1984, I have been told that (I think this have not change since then):

if n is an array,
n[5] is the same as *(n+5) so it is definitevely not an address.
n is the same as &n[0] and is the starting address of the array
&n[5] is the address of the 5th element, and is the same as n+5

Also note that:
if n is declared to be an array of int*16, n+5 is still the address of the 5th element because the compiler takes care of the type of n. So if n is an float (4 byte length), n+5 is still pointing to the 5th element.

Hope it will help you.
treitmey



Joined: 23 Jan 2004
Posts: 1094
Location: Appleton,WI USA

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PostPosted: Wed Oct 06, 2004 9:37 am     Reply with quote

I think we are saying the same thing.
Yes the name is an address to ellement 0.
If you have a funtion that requires an address,... for example an address to an int8.

int8 tmp[3];

Then you can pass in the array name.

function(tmp)
or
function(&tmp[2])

This is how I use it.


Code:

int8 RX_BUF[260];
pkt.calcCS=chksum(&RX_BUF[rx_indx_o],pktsz-1);

int8 chksum(char *data,int8 size)
{
  int8 x;
  int8 chksum=0;
  for (x=0;x<size;x++,data++)
  {
    chksum=chksum+*data;
    }
  return(chksum);
}



Last edited by treitmey on Wed Oct 06, 2004 9:44 am; edited 1 time in total
Guest








PostPosted: Wed Oct 06, 2004 9:41 am     Reply with quote

treitmey wrote:
I think we are saying the same thing.
Yes the name is an address to ellement 0.
If you have a funtion that requires an address,... for example an address to an int8.

int8 tmp[3];

Then you can pass in the array name.

function(tmp)
or
function(&tmp[3])

This is how I use it.


Code:

int8 RX_BUF[260];
pkt.calcCS=chksum(&RX_BUF[rx_indx_o],pktsz-1);

int8 chksum(char *data,int8 size)
{
  int8 x;
  int8 chksum=0;
  for (x=0;x<size;x++,data++)
  {
    chksum=chksum+*data;
    }
  return(chksum);
}



I think that calling function(&tmp[3]) will pass a pointer to the 4th element of the tmp array; as this is a 3 element array (subscripts from 0 to 2) the function will receive a pointer to a "undefined" portion of memory.

Calling funcion (&tmp[0]) or function (tmp) is effectivly exactely the same thing.

Bye.
treitmey



Joined: 23 Jan 2004
Posts: 1094
Location: Appleton,WI USA

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PostPosted: Wed Oct 06, 2004 9:44 am     Reply with quote

yup,.. bad array example. (fixed)
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