mpfj
Joined: 09 Sep 2003 Posts: 95 Location: UK
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Posted: Thu Apr 13, 2006 6:59 am |
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Anonymous wrote: | How will the FM24C256 have enough memory for this application? It has only 256 kbit.. I think he picked the wrong chip. |
As I stated at the start of the thread ...
mpfj wrote: | You need 2 x 650 x 8 = 10,400 bytes. |
10,400 bytes is 83,200 bits. This will easily fit into a 256k bit device (which has 262,144 bits) ... |
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